What is area y= 1/(sqrt(1-8x)),-10<= x<= 0 ?

The answer to area y= 1/(sqrt(1-8x)),-10<= x<= 0 is 2

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area y= 1/(sqrt(1-8x)),-10<= x<= 0

area

y = \frac{1}{1 - 8 x}, - 10 \leq x \leq 0

2

Solution steps

Apply the area formula:

\int_{- 10}^{0} \frac{1}{1 - 8 x} d x

Solve

\int_{- 10}^{0} \frac{1}{1 - 8 x} d x : 2

The area is:

= 2

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What is area y= 1/(sqrt(1-8x)),-10<= x<= 0 ?
The answer to area y= 1/(sqrt(1-8x)),-10<= x<= 0 is 2