What is the derivative of ln(e^{sin(x}*x^{cos(x)})) ?

The derivative of ln(e^{sin(x}*x^{cos(x)})) is cos(x)+(cos(x))/x-ln(x)sin(x)

What is the first derivative of ln(e^{sin(x}*x^{cos(x)})) ?

The first derivative of ln(e^{sin(x}*x^{cos(x)})) is cos(x)+(cos(x))/x-ln(x)sin(x)

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\frac{d}{d x} (ln (e^{s i n (x)} \cdot x^{c o s (x)}))

cos (x) + \frac{cos ( x )}{x} - ln (x) sin (x)

Solution steps

\frac{d}{d x} (ln (e^{s i n (x)} x^{c o s (x)}))

Apply the chain rule:

\frac{1}{e ^{s i n (x)} x ^{c o s (x)}} \frac{d}{d x} (e^{s i n (x)} x^{c o s (x)})

= \frac{1}{e ^{s i n (x)} x ^{c o s (x)}} \frac{d}{d x} (e^{s i n (x)} x^{c o s (x)})

\frac{d}{d x} (e^{s i n (x)} x^{c o s (x)}) = e^{s i n (x)} cos (x) x^{c o s (x)} + x^{c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x}) e^{s i n (x)}

= \frac{1}{e ^{s i n (x)} x ^{c o s (x)}} (e^{s i n (x)} cos (x) x^{c o s (x)} + x^{c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x}) e^{s i n (x)})

Simplify

\frac{1}{e ^{s i n (x)} x ^{c o s (x)}} (e^{s i n (x)} cos (x) x^{c o s (x)} + x^{c o s (x)} (- sin (x) ln (x) + \frac{cos ( x )}{x}) e^{s i n (x)}) : cos (x) + \frac{cos ( x )}{x} - ln (x) sin (x)

= cos (x) + \frac{cos ( x )}{x} - ln (x) sin (x)

x \to - 1 lim (x^{3} + 3 x^{2} - 2 x - 3)

t y^{^{'}} + 4 y = t^{3}, y (2) = 4

\frac{d}{d x} (\frac{w}{1 - 4 x ^{2}})

2 t^{- \frac{1}{4}} + 2 ln (t) + ln (5)

y^{^{''}} - y^{^{'}} + 0.25 y = 0

What is the derivative of ln(e^{sin(x}*x^{cos(x)})) ?
The derivative of ln(e^{sin(x}*x^{cos(x)})) is cos(x)+(cos(x))/x-ln(x)sin(x)
What is the first derivative of ln(e^{sin(x}*x^{cos(x)})) ?
The first derivative of ln(e^{sin(x}*x^{cos(x)})) is cos(x)+(cos(x))/x-ln(x)sin(x)