What is the limit as t approaches 1 of sqrt(t+4) ?

The limit as t approaches 1 of sqrt(t+4) is square root of 5

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limit as t approaches 1 of sqrt(t+4)

t \to 1 lim (t + 4)

5

Solution steps

t \to 1 lim (t + 4)

Plug in the value

t = 1

= 1 + 4

Simplify

= 5

x \to 5 lim (- (x - 3)^{2})

\frac{d}{d t} (1.1 t + 6.3 t^{3})

x \to \infty lim ((\frac{x + 1}{x + 2})^{\frac{- 4 x}{5}})

f (x) = \frac{x ^{3} + 7}{x}

\int \frac{3}{x ^{5}} d x

What is the limit as t approaches 1 of sqrt(t+4) ?
The limit as t approaches 1 of sqrt(t+4) is square root of 5