What is the derivative of f(x)= 9/(x^2) ?

The derivative of f(x)= 9/(x^2) is -(18)/(x^3)

What is the first derivative of f(x)= 9/(x^2) ?

The first derivative of f(x)= 9/(x^2) is -(18)/(x^3)

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derivative of

f (x) = \frac{9}{x ^{2}}

- \frac{18}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{9}{x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 9 (- 2 x^{- 2 - 1})

Simplify

9 (- 2 x^{- 2 - 1}) : - \frac{18}{x ^{3}}

= - \frac{18}{x ^{3}}

- 9 y^{^{''}} + 36 y = 0, y (1) = 1, y^{^{'}} (- 1) = - 2

x \to \infty lim (\frac{- 2}{0})

x \to \infty lim (\frac{( sin ^{2} ( x ) )}{x + e ^{- x}})

y = \frac{x}{x + 9}

\frac{s + 1}{s ^{2} + 3 s + 2}

What is the derivative of f(x)= 9/(x^2) ?
The derivative of f(x)= 9/(x^2) is -(18)/(x^3)
What is the first derivative of f(x)= 9/(x^2) ?
The first derivative of f(x)= 9/(x^2) is -(18)/(x^3)