What is (\partial)/(\partial x)(7xy^4+2) ?

The answer to (\partial)/(\partial x)(7xy^4+2) is 7y^4

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(\partial)/(\partial x)(7xy^4+2)

\frac{\partial}{\partial x} (7 x y^{4} + 2)

7 y^{4}

Solution steps

\frac{\partial}{\partial x} (7 x y^{4} + 2)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (7 x y^{4}) + \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (7 x y^{4}) = 7 y^{4}

\frac{\partial}{\partial x} (2) = 0

= 7 y^{4} + 0

Simplify

= 7 y^{4}

\int \frac{1}{( x + 1 ) ( x ^{2} + 25 )} d x

\int (x^{\frac{3}{2}} + 8)^{6} x d x

n = 1 \sum \infty (- \frac{10}{11})^{n}

\frac{d}{d x} (\frac{x}{y ^{2}} - \frac{y}{x ^{2}})

f (x) = \frac{1}{1 + x ^{2}}, at x = - 1

What is (\partial)/(\partial x)(7xy^4+2) ?
The answer to (\partial)/(\partial x)(7xy^4+2) is 7y^4