What is the integral from 0 to 1 of y/(e^{2y)} ?

The integral from 0 to 1 of y/(e^{2y)} is -3/(4e^2)+1/4

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integral from 0 to 1 of y/(e^{2y)}

\int_{0}^{1} \frac{y}{e ^{2 y}} d y

- \frac{3}{4 e ^{2}} + \frac{1}{4}

Solution steps

\int_{0}^{1} \frac{y}{e ^{2 y}} d y

Apply Integration By Parts

: [- \frac{1}{2} e^{- 2 y} y - \int - \frac{1}{2} e^{- 2 y} d y]_{0}^{1}

= [- \frac{1}{2} e^{- 2 y} y - \int - \frac{1}{2} e^{- 2 y} d y]_{0}^{1}

\int - \frac{1}{2} e^{- 2 y} d y = \frac{1}{4} e^{- 2 y}

= [- \frac{1}{2} e^{- 2 y} y - \frac{1}{4} e^{- 2 y}]_{0}^{1}

Compute the boundaries:

- \frac{3}{4 e ^{2}} + \frac{1}{4}

= - \frac{3}{4 e ^{2}} + \frac{1}{4}

\frac{\partial}{\partial y} (x y^{3} z^{2})

\frac{d}{d x} (x^{2} - \frac{2}{x ^{2}})

\frac{\partial}{\partial x} (x \cdot Y (x))

(- 7, - 4), (- 2, 3)

x \to \infty lim (4 - \frac{3}{x})

What is the integral from 0 to 1 of y/(e^{2y)} ?
The integral from 0 to 1 of y/(e^{2y)} is -3/(4e^2)+1/4