What is the tangent of y=x^2-x^4,(1,0) ?

The tangent of y=x^2-x^4,(1,0) is y=-2x+2

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tangent of y=x^2-x^4,(1,0)

tangent of

y = x^{2} - x^{4}, (1, 0)

y = - 2 x + 2

Solution steps

Find the slope of

y = x^{2} - x^{4} : \frac{d y}{d x} = 2 x - 4 x^{3}

Compute the slope of

y = x^{2} - x^{4}

(1, 0) : m = - 2

Find the line with slope m=

- 2

and passing through

(1, 0) : y = - 2 x + 2

y = - 2 x + 2

\int_{1}^{6} \frac{7}{x ^{2}} d x

\frac{d}{d x} (3 csc (x) + 7 cos (x))

\frac{d}{d x} (\frac{x + 1}{x + 1})

\frac{\partial}{\partial z} (9 e^{x} cos (yz))

f (x) = x^{3} 2 x + 1

What is the tangent of y=x^2-x^4,(1,0) ?
The tangent of y=x^2-x^4,(1,0) is y=-2x+2