What is the first derivative of 2(x+1) ?

The first derivative of 2(x+1) is 2

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derivative of 2(x+1)

\frac{d}{d x} (2 (x + 1))

2

Solution steps

\frac{d}{d x} (2 (x + 1))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 2 (\frac{d x}{d x} + \frac{d}{d x} (1))

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= 2 (1 + 0)

Simplify

= 2

ln (1 - x)

\frac{d}{d t} (ln (2 t + 1))

\int \frac{1}{3 x + 1} d x

\int 64 d x

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