What is the solution for x((dy)/(dx))+y/((x+1))=x(x+1) ?

The solution for x((dy)/(dx))+y/((x+1))=x(x+1) is y=(c_{1}(x+1))/x-(x+1}{2x}+\frac{x(x+1))/2

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x((dy)/(dx))+y/((x+1))=x(x+1)

x (\frac{d y}{d x}) + \frac{y}{( x + 1 )} = x (x + 1)

y = \frac{c _{1} ( x + 1 )}{x} - \frac{x + 1}{2 x} + \frac{x ( x + 1 )}{2}

Solution steps

x (\frac{d y}{d x}) + \frac{y}{( x + 1 )} = x (x + 1)

Solve linear ODE:

y = \frac{c _{1} ( x + 1 )}{x} - \frac{x + 1}{2 x} + \frac{x ( x + 1 )}{2}

y = \frac{c _{1} ( x + 1 )}{x} - \frac{x + 1}{2 x} + \frac{x ( x + 1 )}{2}

\int x (3 x + 1)^{9} d x

\int_{- \infty}^{6} x e^{\frac{x}{3}} d x

y^{^{'}} = cos^{2} (t) cos^{2} (2 y)

x \to 0 lim (1 - cot (x))

\frac{t}{( t - 7 ) ^{2}}

What is the solution for x((dy)/(dx))+y/((x+1))=x(x+1) ?
The solution for x((dy)/(dx))+y/((x+1))=x(x+1) is y=(c_{1}(x+1))/x-(x+1}{2x}+\frac{x(x+1))/2