What is the derivative of (x^2-1/(x+3)) ?

The derivative of (x^2-1/(x+3)) is (x^2+6x+1)/((x+3)^2)

What is the first derivative of (x^2-1/(x+3)) ?

The first derivative of (x^2-1/(x+3)) is (x^2+6x+1)/((x+3)^2)

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\frac{d}{d x} (\frac{x ^{2} - 1}{x + 3})

\frac{x ^{2} + 6 x + 1}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 1}{x + 3})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} - 1 ) ( x + 3 ) - \frac{d}{d x} ( x + 3 ) ( x ^{2} - 1 )}{( x + 3 ) ^{2}}

\frac{d}{d x} (x^{2} - 1) = 2 x

\frac{d}{d x} (x + 3) = 1

= \frac{2 x ( x + 3 ) - 1 \cdot ( x ^{2} - 1 )}{( x + 3 ) ^{2}}

Simplify

\frac{2 x ( x + 3 ) - 1 \cdot ( x ^{2} - 1 )}{( x + 3 ) ^{2}} : \frac{x ^{2} + 6 x + 1}{( x + 3 ) ^{2}}

= \frac{x ^{2} + 6 x + 1}{( x + 3 ) ^{2}}

\int \frac{1}{25 - x ^{2}} d x

\int \frac{2 x ^{2}}{e ^{x}} d x

f^{^{'}} (x) = 0.7 sin (x) - 1.1 cos (x)

\frac{t}{2}

\frac{d}{d x} (\frac{cot ( x )}{x + 1})

What is the derivative of (x^2-1/(x+3)) ?
The derivative of (x^2-1/(x+3)) is (x^2+6x+1)/((x+3)^2)
What is the first derivative of (x^2-1/(x+3)) ?
The first derivative of (x^2-1/(x+3)) is (x^2+6x+1)/((x+3)^2)