What is inverse oflaplace s/(s^2) ?

The answer to inverse oflaplace s/(s^2) is 1

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inverse oflaplace s/(s^2)

inverse laplace

\frac{s}{s ^{2}}

1

Solution steps

L^{- 1} {\frac{s}{s ^{2}}}

Apply inverse transform rule:

L^{- 1} {F (s)} = f (t)

then

L^{- 1} {s F (s)} = \frac{d}{d t} f (t) + f (0)

For

\frac{s}{s ^{2}} : F (s) = \frac{1}{s ^{2}}

= \frac{d}{d t} (L^{- 1} {\frac{1}{s ^{2}}}) + L^{- 1} {\frac{1}{s ^{2}}} (0)

L^{- 1} {\frac{1}{s ^{2}}} : t

\frac{d t}{d t} = 1

Evaluate

t

at point

0 = 0

= 1

\frac{\partial}{\partial x} (e^{- x} cos (x))

9 y ln (x) - x y^{^{'}} = 0

36 y^{^{''}} + 84 y^{^{'}} + 49 y = 0

(x sin (3 x))^{^{'}}

\frac{d}{d x} (\frac{tan ( x )}{cos ( x ) - 4 x})

What is inverse oflaplace s/(s^2) ?
The answer to inverse oflaplace s/(s^2) is 1