What is the derivative of ln(2x+5) ?

The derivative of ln(2x+5) is 2/(2x+5)

What is the first derivative of ln(2x+5) ?

The first derivative of ln(2x+5) is 2/(2x+5)

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derivative of

ln (2 x + 5)

\frac{2}{2 x + 5}

Solution steps

\frac{d}{d x} (ln (2 x + 5))

Apply the chain rule:

\frac{1}{2 x + 5} \frac{d}{d x} (2 x + 5)

= \frac{1}{2 x + 5} \frac{d}{d x} (2 x + 5)

\frac{d}{d x} (2 x + 5) = 2

= \frac{1}{2 x + 5} \cdot 2

Simplify

\frac{1}{2 x + 5} \cdot 2 : \frac{2}{2 x + 5}

= \frac{2}{2 x + 5}

sin (x^{2})

\int e^{2 t} t d t

f (x) = 3 x^{2} - 5 x - 1 + e^{- x}, at x = 0

\int 2 x^{2} - 10 x d x

\int \frac{40}{16 - x ^{2}} d x

What is the derivative of ln(2x+5) ?
The derivative of ln(2x+5) is 2/(2x+5)
What is the first derivative of ln(2x+5) ?
The first derivative of ln(2x+5) is 2/(2x+5)