What is (\partial)/(\partial x)(e^{x+xy-2y}) ?

The answer to (\partial)/(\partial x)(e^{x+xy-2y}) is e^{x+xy-2y}(y+1)

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(\partial)/(\partial x)(e^{x+xy-2y})

\frac{\partial}{\partial x} (e^{x + x y - 2 y})

e^{x + x y - 2 y} (y + 1)

Solution steps

\frac{\partial}{\partial x} (e^{x + x y - 2 y})

Treat

y

as a constant

Apply the chain rule:

e^{x + x y - 2 y} \frac{\partial}{\partial x} (x + x y - 2 y)

= e^{x + x y - 2 y} \frac{\partial}{\partial x} (x + x y - 2 y)

\frac{\partial}{\partial x} (x + x y - 2 y) = y + 1

= e^{x + x y - 2 y} (y + 1)

\int_{0}^{0.5} 600 x d x

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\frac{d ^{2}}{d x ^{2}} (4 y^{2} + 7 x^{2})

\frac{d}{d x} (- 2 A e^{- 2 x})

\int x sin (x^{2}) d x

What is (\partial)/(\partial x)(e^{x+xy-2y}) ?
The answer to (\partial)/(\partial x)(e^{x+xy-2y}) is e^{x+xy-2y}(y+1)