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Popular >

tangent of y=x^5,(-1,-1)

Solution

tangent of

y = x^{5}, (- 1, - 1)

Solution

y = 5 x + 4

Solution steps

Find the slope of

y = x^{5} : \frac{d y}{d x} = 5 x^{4}

Compute the slope of

y = x^{5}

at

(- 1, - 1) : m = 5

Find the line with slope m=

5

and passing through

(- 1, - 1) : y = 5 x + 4

y = 5 x + 4

Popular Examples

derivative of 1/(2sqrt(x)+1/(4x^{3/4)})

\frac{d}{d x} (\frac{1}{2 x} + \frac{1}{4 x ^{\frac{3}{4}}})

(\partial)/(\partial y)((3x-y)/(5xy+9))

\frac{\partial}{\partial y} (\frac{3 x - y}{5 x y + 9})

xy^'-y=x^2sin(x)

x y^{^{'}} - y = x^{2} sin (x)

(dx)/(dy)=5x(6-x)

\frac{d x}{d y} = 5 x (6 - x)

(\partial)/(\partial x)(-(2x^2)/(5y^2))

\frac{\partial}{\partial x} (- \frac{2 x ^{2}}{5 y ^{2}})

Frequently Asked Questions (FAQ)

What is the tangent of y=x^5,(-1,-1) ?
The tangent of y=x^5,(-1,-1) is y=5x+4