What is the integral of-2x^4-4x^2-5 ?

The integral of-2x^4-4x^2-5 is -(2x^5)/5-(4x^3)/3-5x+C

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integral of-2x^4-4x^2-5

\int - 2 x^{4} - 4 x^{2} - 5 d x

- \frac{2 x ^{5}}{5} - \frac{4 x ^{3}}{3} - 5 x + C

Solution steps

\int - 2 x^{4} - 4 x^{2} - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 2 x^{4} d x - \int 4 x^{2} d x - \int 5 d x

\int 2 x^{4} d x = \frac{2 x ^{5}}{5}

\int 4 x^{2} d x = \frac{4 x ^{3}}{3}

\int 5 d x = 5 x

= - \frac{2 x ^{5}}{5} - \frac{4 x ^{3}}{3} - 5 x

Add a constant to the solution

= - \frac{2 x ^{5}}{5} - \frac{4 x ^{3}}{3} - 5 x + C

\frac{d}{d x} (cot (\frac{π}{2}))

\frac{d ^{2} y}{d x ^{2}} (x^{2}) - 9 x \frac{d y}{d x} + (61 y) = 0

x \to - 1 lim (2 x^{2} + 3 x - 5)

(f (6 x))^{2} + 3

(6, 0), (4, 6)

What is the integral of-2x^4-4x^2-5 ?
The integral of-2x^4-4x^2-5 is -(2x^5)/5-(4x^3)/3-5x+C