What is the integral of sec^2(4x)y ?

The integral of sec^2(4x)y is y 1/4 tan(4x)+C

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integral of sec^2(4x)y

\int sec^{2} (4 x) y d x

y \frac{1}{4} tan (4 x) + C

Solution steps

\int sec^{2} (4 x) y d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= y \cdot \int sec^{2} (4 x) d x

Apply u-substitution

: \int sec^{2} (u) \frac{1}{4} d u

= y \cdot \int sec^{2} (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= y \frac{1}{4} \cdot \int sec^{2} (u) d u

Use the common integral:

\int sec^{2} (u) d u = tan (u)

= y \frac{1}{4} tan (u)

Substitute back

u = 4 x

= y \frac{1}{4} tan (4 x)

Add a constant to the solution

= y \frac{1}{4} tan (4 x) + C

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What is the integral of sec^2(4x)y ?
The integral of sec^2(4x)y is y 1/4 tan(4x)+C