What is the tangent of f(x)=3x^2-4x+5 ?

The tangent of f(x)=3x^2-4x+5 is y=(6a_{0}-4)x-3a_{0}^2+5

Popular >

tangent of f(x)=3x^2-4x+5

tangent of

f (x) = 3 x^{2} - 4 x + 5

y = (6 a_{0} - 4) x - 3 a_{0}^{2} + 5

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0}^{2} - 4 a_{0} + 5)

Find the slope of

f (x) = 3 x^{2} - 4 x + 5 : \frac{df ( x )}{d x} = 6 x - 4

Compute the slope of

f (x) = 3 x^{2} - 4 x + 5

x = a_{0} : m = 6 a_{0} - 4

Find the line with slope m=

6 a_{0} - 4

and passing through

(a_{0}, 3 a_{0}^{2} - 4 a_{0} + 5) : y = (6 a_{0} - 4) x - 3 a_{0}^{2} + 5

y = (6 a_{0} - 4) x - 3 a_{0}^{2} + 5

\frac{d}{d x} (ln (tanh (2 x)))

y^{^{''}} - 3 y^{^{'}} - 4 y = 10 e^{- x} + 4 x + 3

\frac{d}{d x} ((5 x - 3) (2 x + 5)^{2})

\frac{2 x}{9 - tan ( x )}

x \to - 4 - lim (\frac{1}{x + 4})

What is the tangent of f(x)=3x^2-4x+5 ?
The tangent of f(x)=3x^2-4x+5 is y=(6a_{0}-4)x-3a_{0}^2+5