What is area y=9x^2-x^3+x,y=x^2+16x ?

The answer to area y=9x^2-x^3+x,y=x^2+16x is 253/12

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area y=9x^2-x^3+x,y=x^2+16x

area

y = 9 x^{2} - x^{3} + x, y = x^{2} + 16 x

\frac{253}{12}

Solution steps

Apply the area formula:

\int_{0}^{5} 9 x^{2} - x^{3} + x - (x^{2} + 16 x) d x

Solve

\int_{0}^{5} 9 x^{2} - x^{3} + x - (x^{2} + 16 x) d x : \frac{253}{12}

The area is:

= \frac{253}{12}

x \to 3 lim (\frac{x ^{2} - 1}{x - 1})

\frac{d}{d x} (e^{x} (x - 7))

\frac{\partial}{\partial x} (y^{3} e^{\frac{x ^{2}}{2 y}})

\frac{f ( x )}{g ( x )}

\int e^{5 x} 3 e^{5 x} + 2 d x

What is area y=9x^2-x^3+x,y=x^2+16x ?
The answer to area y=9x^2-x^3+x,y=x^2+16x is 253/12