What is the tangent of y=xsqrt(x),\at x=16 ?

The tangent of y=xsqrt(x),\at x=16 is y=6x-32

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tangent of y=xsqrt(x),\at x=16

tangent of

y = x x, at x = 16

y = 6 x - 32

Solution steps

Find the tangent point:

(16, 64)

Find the slope of

y = x x : \frac{d y}{d x} = \frac{3 x}{2}

Compute the slope of

y = x x

x = 16 : m = 6

Find the line with slope m=

6

and passing through

(16, 64) : y = 6 x - 32

y = 6 x - 32

x \to 3 lim (10 - x)

\int - 4 e^{(- \frac{x}{4})} d x

\int \frac{x}{x ( x - 4 )} d x

\int 16 sin (x) cos^{2} (x) d x

x \to - 3 lim (x^{2})

What is the tangent of y=xsqrt(x),\at x=16 ?
The tangent of y=xsqrt(x),\at x=16 is y=6x-32