What is the integral of (e^x)/(e^x+4) ?

The integral of (e^x)/(e^x+4) is ln|e^x+4|+C

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integral of (e^x)/(e^x+4)

\int \frac{e ^{x}}{e ^{x} + 4} d x

ln ∣ e^{x} + 4 ∣ + C

Solution steps

\int \frac{e ^{x}}{e ^{x} + 4} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = e^{x} + 4

= ln ∣ e^{x} + 4 ∣

Add a constant to the solution

= ln ∣ e^{x} + 4 ∣ + C

y = x^{3}, x = y^{2}

\int ln (\frac{x}{x ^{2}}) d x

f (x) = \frac{cos ( x )}{x}

- cos (3 x) \cdot 3

\int \frac{1}{a x ^{2} + b x} d x

What is the integral of (e^x)/(e^x+4) ?
The integral of (e^x)/(e^x+4) is ln|e^x+4|+C