What is the derivative of y=3x^2+14x-5 ?

The derivative of y=3x^2+14x-5 is 6x+14

What is the first derivative of y=3x^2+14x-5 ?

The first derivative of y=3x^2+14x-5 is 6x+14

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derivative of

y = 3 x^{2} + 14 x - 5

6 x + 14

Solution steps

\frac{d}{d x} (3 x^{2} + 14 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (14 x) - \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (14 x) = 14

\frac{d}{d x} (5) = 0

= 6 x + 14 - 0

Simplify

= 6 x + 14

\frac{d y}{d x} = \frac{1}{10} y - \frac{1}{5000} y^{2}, y (0) = 50

x \to 0 lim (\frac{2 x}{2 x + 7})

\frac{d}{d x} ((2 x + 1) (x^{2} + 3))

f (x) = (x - 1)^{3}

x \to - 2 lim (\frac{- x}{x + 2})

What is the derivative of y=3x^2+14x-5 ?
The derivative of y=3x^2+14x-5 is 6x+14
What is the first derivative of y=3x^2+14x-5 ?
The first derivative of y=3x^2+14x-5 is 6x+14