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Popular >

y^'+(4y)/x =-3/x

Solution

y^{^{'}} + \frac{4 y}{x} = - \frac{3}{x}

Solution

y = \frac{c _{1}}{4 x ^{4}} - \frac{3}{4}

Solution steps

y^{'} (x) + \frac{4 y}{x} = - \frac{3}{x}

Solve separable ODE:

y = \frac{c _{1}}{4 x ^{4}} - \frac{3}{4}

y = \frac{c _{1}}{4 x ^{4}} - \frac{3}{4}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+(4y)/x =-3/x ?
The solution for y^'+(4y)/x =-3/x is y=(c_{1})/(4x^4)-3/4