What is the solution for (dy)/(dx)=4xe^{3y} ?

The solution for (dy)/(dx)=4xe^{3y} is y=-(ln(-6x^2-c_{1}))/3

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(dy)/(dx)=4xe^{3y}

\frac{d y}{d x} = 4 x e^{3 y}

y = - \frac{ln ( - 6 x ^{2} - c _{1} )}{3}

Solution steps

\frac{d y}{d x} = 4 x e^{3 y}

Solve separable ODE:

y = - \frac{ln ( - 6 x ^{2} - c _{1} )}{3}

y = - \frac{ln ( - 6 x ^{2} - c _{1} )}{3}

x y^{^{'}} + 2 y = 4 cos (x)

\frac{d y}{d x} = sec^{2} (x) (2 + y)^{2}

\frac{4 e ^{- 2 s}}{3 s ^{2} + 48}

(2 y^{2} x - 3) d x + (2 y x^{2} + 4) d y = 0

\frac{s + 6}{s ^{2} + 6 s + 25}

What is the solution for (dy)/(dx)=4xe^{3y} ?
The solution for (dy)/(dx)=4xe^{3y} is y=-(ln(-6x^2-c_{1}))/3