What is area y=x^3-2x^2+2,y=3x^2+5x-23 ?

The answer to area y=x^3-2x^2+2,y=3x^2+5x-23 is (-75sqrt(5)+625)/3+75sqrt(5)-225

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area y=x^3-2x^2+2,y=3x^2+5x-23

area

y = x^{3} - 2 x^{2} + 2, y = 3 x^{2} + 5 x - 23

\frac{- 75 5 + 625}{3} + 755 - 225

Decimal Notation

95.13673 \dots

Solution steps

Apply the area formula:

\int_{- 5}^{5} x^{3} - 2 x^{2} + 2 - (3 x^{2} + 5 x - 23) d x

Solve

\int_{- 5}^{5} x^{3} - 2 x^{2} + 2 - (3 x^{2} + 5 x - 23) d x : \frac{- 75 5 + 625}{3} + 755 - 225

The area is:

= \frac{- 75 5 + 625}{3} + 755 - 225

\frac{( x ^{2} + 1 ) d y}{d x} + 6 x (y - 1) = 0, y (0) = 3

t \frac{d y}{d t} = (t^{3} + 22 t^{3} \cdot y)

\int \frac{x ^{8}}{1 + x ^{18}} d x

\frac{d}{d x} (2 x e^{x^{2} - 1})

f (30) = \frac{850}{d}

What is area y=x^3-2x^2+2,y=3x^2+5x-23 ?
The answer to area y=x^3-2x^2+2,y=3x^2+5x-23 is (-75sqrt(5)+625)/3+75sqrt(5)-225