What is area x=-2,x=2,y=8x,y=x^2-9 ?

The answer to area x=-2,x=2,y=8x,y=x^2-9 is 124/3

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area x=-2,x=2,y=8x,y=x^2-9

area

x = - 2, x = 2, y = 8 x, y = x^{2} - 9

\frac{124}{3}

Decimal Notation

41.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} 8 x - (x^{2} - 9) d x

Solve

\int_{- 2}^{2} 8 x - (x^{2} - 9) d x : \frac{124}{3}

The area is:

= \frac{124}{3}

\frac{d}{d x} (lo g_{2} (x - 1))

x \to - 4 + lim (\frac{2}{x ^{2} - 16})

\int sin^{2} (x) cos^{3} (d) x d x

ln^{2} (8 x^{2})

\int \frac{1}{2} ln x^{2} + 1 d x

What is area x=-2,x=2,y=8x,y=x^2-9 ?
The answer to area x=-2,x=2,y=8x,y=x^2-9 is 124/3