What is the d/(da)(sin^4(a)-cos^4(a)) ?

The d/(da)(sin^4(a)-cos^4(a)) is 2sin(2a)

What is the first d/(da)(sin^4(a)-cos^4(a)) ?

The first d/(da)(sin^4(a)-cos^4(a)) is 2sin(2a)

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\frac{d}{d a} (sin^{4} (a) - cos^{4} (a))

2 sin (2 a)

Solution steps

\frac{d}{d a} (sin^{4} (a) - cos^{4} (a))

Simplify

sin^{4} (a) - cos^{4} (a) : - cos (2 a)

= \frac{d}{d a} (- cos (2 a))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d a} (cos (2 a))

Apply the chain rule:

- sin (2 a) \frac{d}{d a} (2 a)

= - sin (2 a) \frac{d}{d a} (2 a)

\frac{d}{d a} (2 a) = 2

= - (- sin (2 a) \cdot 2)

Simplify

= 2 sin (2 a)

\frac{1}{4} y^{^{''}} + 4 y = 2 tan (4 t) - \frac{1}{3} e^{3 t}

\int (1 + y^{2}) d y

\frac{\partial}{\partial x} (3 x \cdot e^{z})

\frac{2}{s ^{2} + 2 s + 10} \cdot \frac{1}{s}

What is the d/(da)(sin^4(a)-cos^4(a)) ?
The d/(da)(sin^4(a)-cos^4(a)) is 2sin(2a)
What is the first d/(da)(sin^4(a)-cos^4(a)) ?
The first d/(da)(sin^4(a)-cos^4(a)) is 2sin(2a)