What is the derivative of sin^{1/2}(2x) ?

The derivative of sin^{1/2}(2x) is 1/(2sqrt(sin(2x)))cos(2x)*2

What is the first derivative of sin^{1/2}(2x) ?

The first derivative of sin^{1/2}(2x) is 1/(2sqrt(sin(2x)))cos(2x)*2

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\frac{d}{d x} (sin^{\frac{1}{2}} (2 x))

\frac{1}{2 sin ( 2 x )} cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (sin (2 x))

Apply the chain rule:

\frac{1}{2 sin ( 2 x )} \frac{d}{d x} (sin (2 x))

= \frac{1}{2 sin ( 2 x )} \frac{d}{d x} (sin (2 x))

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

= \frac{1}{2 sin ( 2 x )} cos (2 x) \cdot 2

\int - 8 (y)^{2} (1) d y

x = y^{2} + 14 y + 16, x = 7 y + 6

2 x + 1

\int + \frac{1}{( 9 x ^{2} + 1 ) ^{\frac{5}{2}}} d x

f (x) = \frac{6 x}{( x ^{3} - 9 ) ^{2}}

What is the derivative of sin^{1/2}(2x) ?
The derivative of sin^{1/2}(2x) is 1/(2sqrt(sin(2x)))cos(2x)*2
What is the first derivative of sin^{1/2}(2x) ?
The first derivative of sin^{1/2}(2x) is 1/(2sqrt(sin(2x)))cos(2x)*2