What is the solution for y^{''}+7y^'+10y=0 ?

The solution for y^{''}+7y^'+10y=0 is y=c_{1}e^{-2t}+c_{2}e^{-5t}

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y^{''}+7y^'+10y=0

y^{^{''}} + 7 y^{^{'}} + 10 y = 0

y = c_{1} e^{- 2 t} + c_{2} e^{- 5 t}

Solution steps

y^{''} (t) + 7 y^{'} (t) + 10 y = 0

Solve linear ODE:

y = c_{1} e^{- 2 t} + c_{2} e^{- 5 t}

y = c_{1} e^{- 2 t} + c_{2} e^{- 5 t}

\int - sinh (x) d x

\frac{d}{d x} (7 x + s + 9)

f (x) = \frac{x ^{2} - 1}{x}

\frac{d}{d x} (\frac{1}{4} x^{4} - \frac{2}{3} x^{3} + 2)

\int ln (x^{2} + 3) d x

What is the solution for y^{''}+7y^'+10y=0 ?
The solution for y^{''}+7y^'+10y=0 is y=c_{1}e^{-2t}+c_{2}e^{-5t}