What is longdivision (x^2+2x+1)/(x^2-2x+1) ?

The solution to longdivision (x^2+2x+1)/(x^2-2x+1) is 1+(4x)/(x^2-2x+1)

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longdivision (x^2+2x+1)/(x^2-2x+1)

long division

\frac{x ^{2} + 2 x + 1}{x ^{2} - 2 x + 1}

1 + \frac{4 x}{x ^{2} - 2 x + 1}

Solution steps

\frac{x ^{2} + 2 x + 1}{x ^{2} - 2 x + 1}

Divide

\frac{x ^{2} + 2 x + 1}{x ^{2} - 2 x + 1} : \frac{x ^{2} + 2 x + 1}{x ^{2} - 2 x + 1} = 1 + \frac{4 x}{x ^{2} - 2 x + 1}

= 1 + \frac{4 x}{x ^{2} - 2 x + 1}

\frac{d}{d x} (e^{x - 6})

y = (2 x^{3} + 1)^{2}

y^{^{'}} + 4 y = 3 x^{2} e^{- 4 x}

\int (sin (x))^{3} (cos (x))^{4} d x

\int \frac{12 sec ^{2} ( x )}{tan ^{7} ( x )} d x

What is longdivision (x^2+2x+1)/(x^2-2x+1) ?
The solution to longdivision (x^2+2x+1)/(x^2-2x+1) is 1+(4x)/(x^2-2x+1)