What is the integral from 1 to infinity of 6/(x^4) ?

The integral from 1 to infinity of 6/(x^4) is 2

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integral from 1 to infinity of 6/(x^4)

\int_{1}^{\infty} \frac{6}{x ^{4}} d x

2

Solution steps

\int_{1}^{\infty} \frac{6}{x ^{4}} d x

Compute the indefinite integral:

\int \frac{6}{x ^{4}} d x = - \frac{2}{x ^{3}} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{6}{x ^{4}} d x = 0 - (- 2)

= 0 - (- 2)

Simplify

= 2

\frac{d ^{6}}{d x ^{6}} (9 + 3 sin (x^{2}))

\frac{\partial}{\partial y} (3 y e^{- z})

\frac{s}{s ^{2} + s + 1}

y = 1 - x^{2}, y = 13 - 7 x

x \to 0 + lim (x^{2} + x)

What is the integral from 1 to infinity of 6/(x^4) ?
The integral from 1 to infinity of 6/(x^4) is 2