What is the solution for (x+3)((dy)/(dx))+y=ln(x) ?

The solution for (x+3)((dy)/(dx))+y=ln(x) is y=(xln(x))/(x+3)-x/(x+3)+(c_{1})/(x+3)

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(x+3)((dy)/(dx))+y=ln(x)

(x + 3) (\frac{d y}{d x}) + y = ln (x)

y = \frac{x ln ( x )}{x + 3} - \frac{x}{x + 3} + \frac{c _{1}}{x + 3}

Solution steps

(x + 3) (\frac{d y}{d x}) + y = ln (x)

Solve linear ODE:

y = \frac{x ln ( x )}{x + 3} - \frac{x}{x + 3} + \frac{c _{1}}{x + 3}

y = \frac{x ln ( x )}{x + 3} - \frac{x}{x + 3} + \frac{c _{1}}{x + 3}

\frac{d ^{2}}{d x ^{2}} ((9 x^{2} + 6)^{6})

\int sin^{4} (\frac{x}{4}) cos (\frac{x}{4}) d x

\frac{\partial}{\partial y} (\frac{2 x}{y})

\frac{d y}{d x} - \frac{( 2 y )}{( 3 x )} + \frac{( x ^{2} + 2 )}{3} \cdot y^{4} = 0

\int e^{x} - ln (x) d x

What is the solution for (x+3)((dy)/(dx))+y=ln(x) ?
The solution for (x+3)((dy)/(dx))+y=ln(x) is y=(xln(x))/(x+3)-x/(x+3)+(c_{1})/(x+3)