What is the derivative of 1-cos(4x) ?

The derivative of 1-cos(4x) is 4sin(4x)

What is the first derivative of 1-cos(4x) ?

The first derivative of 1-cos(4x) is 4sin(4x)

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\frac{d}{d x} (1 - cos (4 x))

4 sin (4 x)

Solution steps

\frac{d}{d x} (1 - cos (4 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (cos (4 x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (cos (4 x)) = - sin (4 x) \cdot 4

= 0 - (- sin (4 x) \cdot 4)

Simplify

= 4 sin (4 x)

\int 2^{x} d x

\int \frac{sin ( w )}{w} d w

f (x) = x - 5, at x = 9

\frac{d}{d x} (3 8 x^{2})

(x^{2} + 5)^{5}

What is the derivative of 1-cos(4x) ?
The derivative of 1-cos(4x) is 4sin(4x)
What is the first derivative of 1-cos(4x) ?
The first derivative of 1-cos(4x) is 4sin(4x)