What is the slope of x^4-18x^2+81 ?

The slope of x^4-18x^2+81 is 4x^3-36x

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slope of x^4-18x^2+81

slope

x^{4} - 18 x^{2} + 81

4 x^{3} - 36 x

Solution steps

y = x^{4} - 18 x^{2} + 81

In order to find the slope of the function, take the derivative of

x^{4} - 18 x^{2} + 81

\frac{d}{d x} (x^{4} - 18 x^{2} + 81) = 4 x^{3} - 36 x

4 x^{3} - 36 x

n = 1 \sum \infty \frac{n}{2 n + 3}

y = 2 x^{3}, (- 2, - 16)

\int_{1}^{4} \frac{2}{x} d x

e^{- 6 t} + \frac{1}{2} e^{- 3 t} + \frac{1}{2} e^{- t}

\int 16 sin^{4} (x) d x