What is the tangent of f(x)=x^2-4/x-10,\at x=8 ?

The tangent of f(x)=x^2-4/x-10,\at x=8 is y= 257/16 x-75

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tangent of f(x)=x^2-4/x-10,\at x=8

tangent of

f (x) = x^{2} - \frac{4}{x} - 10, at x = 8

y = \frac{257}{16} x - 75

Solution steps

Find the tangent point:

(8, \frac{107}{2})

Find the slope of

f (x) = x^{2} - \frac{4}{x} - 10 : \frac{df ( x )}{d x} = 2 x + \frac{4}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{257}{16}

Find the line with slope m=

\frac{257}{16}

and passing through

(8, \frac{107}{2}) : y = \frac{257}{16} x - 75

y = \frac{257}{16} x - 75

6 x^{2}

(2 x + 1)^{2} (0.1)

x^{2} - 2 x, - x^{2} + 2 x

\int (e^{8 x} + 4 e^{- x}) d x

\int 7 x - 2 d x

What is the tangent of f(x)=x^2-4/x-10,\at x=8 ?
The tangent of f(x)=x^2-4/x-10,\at x=8 is y= 257/16 x-75