What is the integral from 1 to 2 of 1/(x^4) ?

The integral from 1 to 2 of 1/(x^4) is 7/24

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integral from 1 to 2 of 1/(x^4)

\int_{1}^{2} \frac{1}{x ^{4}} d x

\frac{7}{24}

Decimal

0.29166 \dots

Solution steps

\int_{1}^{2} \frac{1}{x ^{4}} d x

Apply the Power Rule

: [- \frac{1}{3 x ^{3}}]_{1}^{2}

= [- \frac{1}{3 x ^{3}}]_{1}^{2}

Compute the boundaries:

\frac{7}{24}

= \frac{7}{24}

x \to 7 lim (\frac{x}{( x - 7 ) ^{2}})

\int \frac{x}{( x + 1 ) ( x ^{2} + 1 )} d x

x \to 3 + lim (\frac{x + 2}{x - 3})

\int \frac{x - 8}{x ^{2} - 7 x + 10} d x

x \to 2 lim (x 20 - x^{2})

What is the integral from 1 to 2 of 1/(x^4) ?
The integral from 1 to 2 of 1/(x^4) is 7/24