What is (d^2)/(dx^2)(3^{x^2-x+5}) ?

The answer to (d^2)/(dx^2)(3^{x^2-x+5}) is ln(3)(ln(3)*3^{x^2-x+5}(2x-1)^2+2*3^{x^2-x+5})

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(d^2)/(dx^2)(3^{x^2-x+5})

\frac{d ^{2}}{d x ^{2}} (3^{x^{2} - x + 5})

ln (3) (ln (3) \cdot 3^{x^{2} - x + 5} (2 x - 1)^{2} + 2 \cdot 3^{x^{2} - x + 5})

Solution steps

\frac{d ^{2}}{d x ^{2}} (3^{x^{2} - x + 5})

\frac{d}{d x} (3^{x^{2} - x + 5}) = ln (3) \cdot 3^{x^{2} - x + 5} (2 x - 1)

= \frac{d}{d x} (ln (3) \cdot 3^{x^{2} - x + 5} (2 x - 1))

\frac{d}{d x} (ln (3) \cdot 3^{x^{2} - x + 5} (2 x - 1)) = ln (3) (ln (3) \cdot 3^{x^{2} - x + 5} (2 x - 1)^{2} + 2 \cdot 3^{x^{2} - x + 5})

= ln (3) (ln (3) \cdot 3^{x^{2} - x + 5} (2 x - 1)^{2} + 2 \cdot 3^{x^{2} - x + 5})

17 y^{^{'}} = y

\int \frac{1}{x 4 x ^{2} + 16} d x

x \to 1 lim (e^{7 x^{3} - 7 x})

x \to 5 lim (29 - x^{2})

\int x (1 + x^{2})^{\frac{1}{2}} d x

What is (d^2)/(dx^2)(3^{x^2-x+5}) ?
The answer to (d^2)/(dx^2)(3^{x^2-x+5}) is ln(3)(ln(3)*3^{x^2-x+5}(2x-1)^2+2*3^{x^2-x+5})