What is the limit as x approaches 0+of (1-cos(x))/x ?

The limit as x approaches 0+of (1-cos(x))/x is 0

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limit as x approaches 0+of (1-cos(x))/x

x \to 0 + lim (\frac{1 - cos ( x )}{x})

0

Solution steps

x \to 0 + lim (\frac{1 - cos ( x )}{x})

Apply L'Hopital's Rule

: x \to 0 + lim (\frac{sin ( x )}{1})

= x \to 0 + lim (\frac{sin ( x )}{1})

Plug in the value

x = 0

= \frac{sin ( 0 )}{1}

Simplify

\frac{sin ( 0 )}{1} : 0

= 0

\int r^{- 3} d r

x \to - 4 lim (\frac{∣ x ∣ - 4}{x + 4})

x \to - 2 π - lim (csc (x))

\frac{d}{d x} (- 7 (x - 13)^{2} + 8 (x - 13) + 5)

- \frac{1}{2} e^{2 x} + e^{x} - 1

What is the limit as x approaches 0+of (1-cos(x))/x ?
The limit as x approaches 0+of (1-cos(x))/x is 0