What is the sum from n=0 to infinity of (0.4)^n ?

The sum from n=0 to infinity of (0.4)^n is 1.66666…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of (0.4)^n

n = 0 \sum \infty (0.4)^{n}

1.66666 \dots

Solution steps

n = 0 \sum \infty 0. 4^{n}

Apply Series Geometric Test:

1.66666 \dots

= 1.66666 \dots

\int \frac{2 z - 5}{7} d z

\int (\frac{x ^{3} - 2 x ^{2} + 4 x}{x}) d x

\frac{d}{d x} (x^{6} 5 x^{2} - x)

y = \frac{5}{1 + x ^{2}}, (5, 0.19231)

\int 9 e^{4 x + e^{4 x}} d x

What is the sum from n=0 to infinity of (0.4)^n ?
The sum from n=0 to infinity of (0.4)^n is 1.66666…