What is (\partial)/(\partial x)(sin(2x+9y-7z)) ?

The answer to (\partial)/(\partial x)(sin(2x+9y-7z)) is cos(2x+9y-7z)*2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(sin(2x+9y-7z))

\frac{\partial}{\partial x} (sin (2 x + 9 y - 7 z))

cos (2 x + 9 y - 7 z) \cdot 2

Solution steps

\frac{\partial}{\partial x} (sin (2 x + 9 y - 7 z))

Treat

y, z

as constants

Apply the chain rule:

cos (2 x + 9 y - 7 z) \frac{\partial}{\partial x} (2 x + 9 y - 7 z)

= cos (2 x + 9 y - 7 z) \frac{\partial}{\partial x} (2 x + 9 y - 7 z)

\frac{\partial}{\partial x} (2 x + 9 y - 7 z) = 2

= cos (2 x + 9 y - 7 z) \cdot 2

\int \frac{1}{1 + e ^{2 x}} d x

\frac{1}{3} x, x + 4, [4, - 1]

\frac{d y}{d x} = \frac{( 1 - y )}{1 + x ^{2}}

y^{^{''}} + 6 y^{^{'}} - 7 y = 0, y (0) = 1, y^{^{'}} (0) = 1

f (x) = \frac{5}{4 x}

What is (\partial)/(\partial x)(sin(2x+9y-7z)) ?
The answer to (\partial)/(\partial x)(sin(2x+9y-7z)) is cos(2x+9y-7z)*2