What is the derivative of x^2sin(x+x) ?

The derivative of x^2sin(x+x) is 2xsin(x)+cos(x)x^2+1

What is the first derivative of x^2sin(x+x) ?

The first derivative of x^2sin(x+x) is 2xsin(x)+cos(x)x^2+1

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\frac{d}{d x} (x^{2} sin (x) + x)

2 x sin (x) + cos (x) x^{2} + 1

Solution steps

\frac{d}{d x} (x^{2} sin (x) + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} sin (x)) + \frac{d x}{d x}

\frac{d}{d x} (x^{2} sin (x)) = 2 x sin (x) + cos (x) x^{2}

\frac{d x}{d x} = 1

= 2 x sin (x) + cos (x) x^{2} + 1

f (x) = \frac{2}{x + 1}

\frac{( x ^{4} - 5 x ^{3} + x ^{\frac{1}{2}} )}{x ^{2}}

\int_{0}^{\infty} 4 x e^{- 2 x} d x

y^{^{''}} + 3 y^{^{'}} + 2 y = 4 t

\frac{d}{d x} (e^{4 x} - 1)

What is the derivative of x^2sin(x+x) ?
The derivative of x^2sin(x+x) is 2xsin(x)+cos(x)x^2+1
What is the first derivative of x^2sin(x+x) ?
The first derivative of x^2sin(x+x) is 2xsin(x)+cos(x)x^2+1