What is (\partial)/(\partial y)(xzt^2sqrt(y+1)) ?

The answer to (\partial)/(\partial y)(xzt^2sqrt(y+1)) is (xzt^2)/(2sqrt(y+1))

Popular >

(\partial)/(\partial y)(xzt^2sqrt(y+1))

\frac{\partial}{\partial y} (x z t^{2} y + 1)

\frac{x z t ^{2}}{2 y + 1}

Solution steps

\frac{\partial}{\partial y} (x z t^{2} y + 1)

Treat

x, z, t

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x z t^{2} \frac{\partial}{\partial y} (y + 1)

Apply the chain rule:

\frac{1}{2 y + 1} \frac{\partial}{\partial y} (y + 1)

= \frac{1}{2 y + 1} \frac{\partial}{\partial y} (y + 1)

\frac{\partial}{\partial y} (y + 1) = 1

= x z t^{2} \frac{1}{2 y + 1} \cdot 1

Simplify

x z t^{2} \frac{1}{2 y + 1} \cdot 1 : \frac{x z t ^{2}}{2 y + 1}

= \frac{x z t ^{2}}{2 y + 1}

f (x) = 9 - 2 x^{2}

f (x) = 6 x e^{x}, at x = 0

\int x (9 - x)^{2} d x

\int \frac{1}{2 x + 2 x} d x

\frac{3}{( 8 z + 16 )}

What is (\partial)/(\partial y)(xzt^2sqrt(y+1)) ?
The answer to (\partial)/(\partial y)(xzt^2sqrt(y+1)) is (xzt^2)/(2sqrt(y+1))