What is the derivative of 2/((x+1(-x+1))) ?

The derivative of 2/((x+1(-x+1))) is (4x)/((x+1)^2(-x+1)^2)

What is the first derivative of 2/((x+1(-x+1))) ?

The first derivative of 2/((x+1(-x+1))) is (4x)/((x+1)^2(-x+1)^2)

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\frac{d}{d x} (\frac{2}{( x + 1 ) ( - x + 1 )})

\frac{4 x}{( x + 1 ) ^{2} ( - x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{( x + 1 ) ( - x + 1 )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{( x + 1 ) ( - x + 1 )})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} (((x + 1) (- x + 1))^{- 1})

Apply the chain rule:

- \frac{1}{( ( x + 1 ) ( - x + 1 ) ) ^{2}} \frac{d}{d x} ((x + 1) (- x + 1))

= - \frac{1}{( ( x + 1 ) ( - x + 1 ) ) ^{2}} \frac{d}{d x} ((x + 1) (- x + 1))

\frac{d}{d x} ((x + 1) (- x + 1)) = - 2 x

= 2 (- \frac{1}{( ( x + 1 ) ( - x + 1 ) ) ^{2}} (- 2 x))

Simplify

2 (- \frac{1}{( ( x + 1 ) ( - x + 1 ) ) ^{2}} (- 2 x)) : \frac{4 x}{( x + 1 ) ^{2} ( - x + 1 ) ^{2}}

= \frac{4 x}{( x + 1 ) ^{2} ( - x + 1 ) ^{2}}

t \to 1 lim (cos (t π))

f (x) = \frac{2}{x ^{3}}

y = \frac{12}{1 + x ^{4}}, y = 6 x^{2}

\int x sin (5 x^{2}) d x

\frac{d}{d x} (arccos (x^{2} + y^{2} - 4))

What is the derivative of 2/((x+1(-x+1))) ?
The derivative of 2/((x+1(-x+1))) is (4x)/((x+1)^2(-x+1)^2)
What is the first derivative of 2/((x+1(-x+1))) ?
The first derivative of 2/((x+1(-x+1))) is (4x)/((x+1)^2(-x+1)^2)