What is the derivative of xln(x^2) ?

The derivative of xln(x^2) is ln(x^2)+2

What is the first derivative of xln(x^2) ?

The first derivative of xln(x^2) is ln(x^2)+2

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derivative of

x ln (x^{2})

ln (x^{2}) + 2

Solution steps

\frac{d}{d x} (x ln (x^{2}))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = ln (x^{2})

= \frac{d x}{d x} ln (x^{2}) + \frac{d}{d x} (ln (x^{2})) x

\frac{d x}{d x} = 1

\frac{d}{d x} (ln (x^{2})) = \frac{2}{x}

= 1 \cdot ln (x^{2}) + \frac{2}{x} x

Simplify

1 \cdot ln (x^{2}) + \frac{2}{x} x : ln (x^{2}) + 2

= ln (x^{2}) + 2

y^{^{''}} + 3 y^{^{'}} + 2 y = 0, y (0) = 1, y^{^{'}} (0) = 0

y = - x^{2} + 7 x, y = x^{2} - 3 x

n = 5 \sum \infty \frac{6 ^{n}}{7 ^{n}}

x \to 0 + lim ((5 x)^{4 x})

f (x) = x cos (x^{2})

What is the derivative of xln(x^2) ?
The derivative of xln(x^2) is ln(x^2)+2
What is the first derivative of xln(x^2) ?
The first derivative of xln(x^2) is ln(x^2)+2