What is the solution for (2x+ye^{y/x})dx-xe^{y/x}dy=0 ?

The solution for (2x+ye^{y/x})dx-xe^{y/x}dy=0 is y=ln(2ln(x)+c_{1})x

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(2x+ye^{y/x})dx-xe^{y/x}dy=0

(2 x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0

y = ln (2 ln (x) + c_{1}) x

Solution steps

(2 x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0

Solve using substitution:

y = ln (2 ln (x) + c_{1}) x

y = ln (2 ln (x) + c_{1}) x

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What is the solution for (2x+ye^{y/x})dx-xe^{y/x}dy=0 ?
The solution for (2x+ye^{y/x})dx-xe^{y/x}dy=0 is y=ln(2ln(x)+c_{1})x