What is (\partial)/(\partial x)(x+xy+y) ?

The answer to (\partial)/(\partial x)(x+xy+y) is y+1

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(\partial)/(\partial x)(x+xy+y)

\frac{\partial}{\partial x} (x + x y + y)

y + 1

Solution steps

\frac{\partial}{\partial x} (x + x y + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (x y) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (y) = 0

= 1 + y + 0

Simplify

= y + 1

\frac{2 x}{x ^{2} + 1}, \frac{x}{13}, [- 5, 5]

3 sin (x), 4 cos (x)

x + 5 x y - 2 x^{3} = 2

y^{^{''}} = x sin (x) + x cos (x)

\int x (x^{2} + 3) d x

What is (\partial)/(\partial x)(x+xy+y) ?
The answer to (\partial)/(\partial x)(x+xy+y) is y+1