What is the solution for y^'+e^xy=sin(x) ?

The solution for y^'+e^xy=sin(x) is y=(integral of sin(x)e^{e^x})/(e^{e^x)}

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y^'+e^xy=sin(x)

y^{^{'}} + e^{x} y = sin (x)

y = \frac{\int sin ( x ) e ^{e^{x}} d x}{e ^{e^{x}}}

Solution steps

y^{'} (x) + e^{x} y = sin (x)

Solve linear ODE:

y = \frac{\int sin ( x ) e ^{e^{x}} d x}{e ^{e^{x}}}

y = \frac{\int sin ( x ) e ^{e^{x}} d x}{e ^{e^{x}}}

\int_{1}^{3} (x^{2} - \frac{1}{4 x ^{2}}) d x

\frac{d y}{d x} = \frac{2 x + y}{2 x + y + 3}

\frac{( x ^{(3)} - 1 ) ( x + 1 ) ^{(3)}}{x + 2}

7 z + 6 z^{\frac{1}{2}} - 8

\frac{d}{d x} ((3 cos (x)) (ln (1 + x)))

What is the solution for y^'+e^xy=sin(x) ?
The solution for y^'+e^xy=sin(x) is y=(integral of sin(x)e^{e^x})/(e^{e^x)}