What is the derivative of (9x^2+6)^6 ?

The derivative of (9x^2+6)^6 is 108x(9x^2+6)^5

What is the first derivative of (9x^2+6)^6 ?

The first derivative of (9x^2+6)^6 is 108x(9x^2+6)^5

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derivative of

(9 x^{2} + 6)^{6}

108 x (9 x^{2} + 6)^{5}

Solution steps

\frac{d}{d x} ((9 x^{2} + 6)^{6})

Apply the chain rule:

6 (9 x^{2} + 6)^{5} \frac{d}{d x} (9 x^{2} + 6)

= 6 (9 x^{2} + 6)^{5} \frac{d}{d x} (9 x^{2} + 6)

\frac{d}{d x} (9 x^{2} + 6) = 18 x

= 6 (9 x^{2} + 6)^{5} \cdot 18 x

Simplify

= 108 x (9 x^{2} + 6)^{5}

\int \frac{7 sec ^{2} ( 2 x )}{3 - 5 tan ( 2 x )} d x

\frac{d}{d x} (\frac{2}{1 - 7 x})

n = 0 \sum \infty \frac{1}{n + 5}

\int \frac{x ^{2}}{( 64 - x ^{2} ) ^{\frac{3}{2}}} d x

(e^{- t} cos (t))^{^{'}}

What is the derivative of (9x^2+6)^6 ?
The derivative of (9x^2+6)^6 is 108x(9x^2+6)^5
What is the first derivative of (9x^2+6)^6 ?
The first derivative of (9x^2+6)^6 is 108x(9x^2+6)^5