What is the derivative of f(x)=sqrt(2x-1) ?

The derivative of f(x)=sqrt(2x-1) is 1/(sqrt(2x-1))

What is the first derivative of f(x)=sqrt(2x-1) ?

The first derivative of f(x)=sqrt(2x-1) is 1/(sqrt(2x-1))

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derivative of

f (x) = 2 x - 1

\frac{1}{2 x - 1}

Solution steps

\frac{d}{d x} (2 x - 1)

Apply the chain rule:

\frac{1}{2 2 x - 1} \frac{d}{d x} (2 x - 1)

= \frac{1}{2 2 x - 1} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= \frac{1}{2 2 x - 1} \cdot 2

Simplify

\frac{1}{2 2 x - 1} \cdot 2 : \frac{1}{2 x - 1}

= \frac{1}{2 x - 1}

x \to \infty lim (\frac{- 1 ^{x + 1} x}{x + x})

\int \frac{sin ( 2 x )}{39 + cos ^{2} ( x )} d x

f (x) = sin (x^{2} + x)

x y^{^{'}} = - y - x

x \to 5 lim (\frac{x + 1}{x + 5})

What is the derivative of f(x)=sqrt(2x-1) ?
The derivative of f(x)=sqrt(2x-1) is 1/(sqrt(2x-1))
What is the first derivative of f(x)=sqrt(2x-1) ?
The first derivative of f(x)=sqrt(2x-1) is 1/(sqrt(2x-1))