What is the integral of 1/(x(\sqrt[6]{x))} ?

The integral of 1/(x(\sqrt[6]{x))} is -6/(\sqrt[6]{x)}+C

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integral of 1/(x(\sqrt[6]{x))}

\int \frac{1}{x ( 6 x )} d x

- \frac{6}{6 x} + C

Solution steps

\int \frac{1}{x 6 x} d x

Simplify

x 6 x : x^{\frac{7}{6}}

= \int \frac{1}{x ^{\frac{7}{6}}} d x

Apply the Power Rule

: - \frac{6}{6 x}

= - \frac{6}{6 x}

Add a constant to the solution

= - \frac{6}{6 x} + C

x \to + 0 + lim (x^{12} ln (x))

\int x^{7} e^{x^{8}} d x

\int_{1}^{3} \frac{x ^{2} + 2}{4 x - x ^{2}} d x

\int \frac{3 x ^{2}}{x ^{3} + 1} d x

y (x - b) + y^{^{'}} b x = 0

What is the integral of 1/(x(\sqrt[6]{x))} ?
The integral of 1/(x(\sqrt[6]{x))} is -6/(\sqrt[6]{x)}+C