What is the derivative of f(x)=sin(x^2+x) ?

The derivative of f(x)=sin(x^2+x) is cos(x^2+x)(2x+1)

What is the first derivative of f(x)=sin(x^2+x) ?

The first derivative of f(x)=sin(x^2+x) is cos(x^2+x)(2x+1)

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derivative of

f (x) = sin (x^{2} + x)

cos (x^{2} + x) (2 x + 1)

Solution steps

\frac{d}{d x} (sin (x^{2} + x))

Apply the chain rule:

cos (x^{2} + x) \frac{d}{d x} (x^{2} + x)

= cos (x^{2} + x) \frac{d}{d x} (x^{2} + x)

\frac{d}{d x} (x^{2} + x) = 2 x + 1

= cos (x^{2} + x) (2 x + 1)

x y^{^{'}} = - y - x

x \to 5 lim (\frac{x + 1}{x + 5})

\int sin^{7} (θ) cos^{5} (θ) d θ

f (x) = 5 x e^{x}, at x = 0

\frac{d}{d x} (\frac{3 x ^{5} - 7 x ^{2} - 4}{x ^{2}})

What is the derivative of f(x)=sin(x^2+x) ?
The derivative of f(x)=sin(x^2+x) is cos(x^2+x)(2x+1)
What is the first derivative of f(x)=sin(x^2+x) ?
The first derivative of f(x)=sin(x^2+x) is cos(x^2+x)(2x+1)